Infinite Series
Definition 22.1. Let {an} be a sequence. For each positive integer n, let sn=a1+a2+⋯+an=n∑k=1ak. An infinite series is the ordered pair of sequences ({an},{sn}).
sn is called the nth partial sum of the infinite series.
Convergent Series
Definition 22.2. Let ∑∞n=1an be an infinite series. If the sequence of partial sums {sn} (sn=a1+⋯+an) converges to L, we say that the infinite series ∑∞n=1an converges to L or that the infinite series ∑∞n=1an has sum L. If the sequence {sn} diverges, we say that the infinite series ∑∞n=1an diverges.
Theorem 22.3
Theorem 22.3. If the infinite series ∑∞n=1an converges, then limn→∞an=0.
Proof. Let {sn} be a partial sum of the infinite series. Let ∑∞n=1an=L=limn→∞sn. Since sn−sn−1=an for all positive integers n (we define s0=0), limn→∞(sn−sn−1)=limn→∞an=L−L=0.◼
The Geometric Series
Theorem 22.4 (The Geometric Series). Let a be a nonzero number. Then (i) ∑∞n=0arn converges to a1−r if |r|<1.
(ii) ∑∞n=0arn diverges if |r|≥1. (r0 is defined to be 1.)
Proof. (i)
Theorem 23.1
Theorem 23.1. Let ∑∞n=1an and ∑∞n=1bn be series, and let c be a real number. If ∑∞n=1an converges to L and ∑∞n=1bn converges to M, then ∑∞n=1(an+bn) converges to L+M, and ∑∞n=1can converges to cL.
Proof. Let {sn} and {tn} be the partial sums of ∑∞n=1an and ∑∞n=1bn. Then {sn+tn} is the partial sum of ∑∞n=1(an+bn). By definition 22.2 and the assumption, limn→∞sn=L,limn→∞tn=M⟹∞∑n=1(an+bn)=limn→∞(sn+tn)=L+M. And similarly, we have ∞∑n=1can=limn→∞csn=cL.◼